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Verify the pythagorean identity.
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\(\Large1+\cot^2\theta=\csc^2\theta\)
@geerky42
cot=cos/sin and csc=1/sin
Yeah, so you would have \[1+\dfrac{\cos^2\theta}{\sin^2\theta} = \dfrac1{\sin^2\theta}\]
Now multiply both sides by \(\sin^2\theta\)
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1+cos^2=1
right? or am I leaving something out?
@geerky42
\[\Large\sin^2\theta + \cos^2\theta = 1\]
IS that enough to verify Pythagorean identify?
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I don't know. is it?
I believe so.
\[\Large\sin^2\theta + \cos^2\theta = 1\] is called "Pythagorean Identity" after all.
okay, thanks!
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