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Mathematics 27 Online
OpenStudy (bloomlocke367):

Verify the pythagorean identity.

OpenStudy (bloomlocke367):

\(\Large1+\cot^2\theta=\csc^2\theta\)

OpenStudy (bloomlocke367):

@geerky42

OpenStudy (bloomlocke367):

cot=cos/sin and csc=1/sin

geerky42 (geerky42):

Yeah, so you would have \[1+\dfrac{\cos^2\theta}{\sin^2\theta} = \dfrac1{\sin^2\theta}\]

geerky42 (geerky42):

Now multiply both sides by \(\sin^2\theta\)

OpenStudy (bloomlocke367):

1+cos^2=1

OpenStudy (bloomlocke367):

right? or am I leaving something out?

OpenStudy (bloomlocke367):

@geerky42

geerky42 (geerky42):

\[\Large\sin^2\theta + \cos^2\theta = 1\]

geerky42 (geerky42):

IS that enough to verify Pythagorean identify?

OpenStudy (bloomlocke367):

I don't know. is it?

geerky42 (geerky42):

I believe so.

geerky42 (geerky42):

\[\Large\sin^2\theta + \cos^2\theta = 1\] is called "Pythagorean Identity" after all.

OpenStudy (bloomlocke367):

okay, thanks!

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