Question

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Answer 1

\[\left(\dfrac{3x^{-4}y^3}{2xy^{-1}}\right)^2\]

Just use these exponent rules: \[(a^b)^c = a^{bc}\] \[\dfrac{a^b}{a^c} = a^{b-c}\]

Answer 2

\[\cdots ~= \left(\dfrac32\cdot\dfrac{x^{-4}}x \cdot \dfrac{y^3}{y^{-1}}\right)^2\]

In parenthesis, apply this rule: \[\dfrac{a^b}{a^c} = a^{b-c}\]

Answer 3

thanks