Ask your own question, for FREE!
Algebra 22 Online
OpenStudy (anonymous):

What is the equation of a parabola with the vertex at (3,4) and the focus at (6,4)? Please help me! ^_^ y=1/12(x-4)^2+3 y=12((x-4)^2+3 x=1/12(y-4)^2+3 x=12(y-4)^2+3 I tried solving it on my own but I got y=8+x^2+9/8 i think I totally messed up :(

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!