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Mathematics 15 Online
OpenStudy (here_to_help15):

HELP

OpenStudy (here_to_help15):

OpenStudy (here_to_help15):

@amistre64 @AriPotta @Hero @Data_LG2

OpenStudy (thebadyboy):

i think c

OpenStudy (here_to_help15):

I thought B

OpenStudy (anonymous):

Tangent... so that means, I think, OA should be perpendicular to AC, which means OA to AC should be 90 degrees. Since BAY is 57.. YAC should be 90-57

OpenStudy (anonymous):

**52 not 57

OpenStudy (aripotta):

that's what i thought too, data

OpenStudy (here_to_help15):

@Data_LG2 so am i correct?

OpenStudy (anonymous):

90-52 ?

OpenStudy (here_to_help15):

I know it is not C

OpenStudy (here_to_help15):

So your saying A or B... ?

OpenStudy (anonymous):

what do you get when you subtract 52 from 90 ? I don't like saying letters though, I want values, sorry xD

OpenStudy (here_to_help15):

lol I am saying is it 53.0

OpenStudy (anonymous):

90-52 = 53? are you sure?

OpenStudy (here_to_help15):

No lol it ='s 38

OpenStudy (here_to_help15):

But there are no choices for 38 is what im saying....

OpenStudy (anonymous):

right, there ya go :P do you understand why? wait what? can you view the question that you have posted? I can see the right answer

OpenStudy (here_to_help15):

OOOOps lol

OpenStudy (here_to_help15):

But wait are you sure sure its 38 ? I must have made an error

OpenStudy (here_to_help15):

Mind if i get 2 answers? @Hero

OpenStudy (here_to_help15):

@e.mccormick ?

OpenStudy (here_to_help15):

You know what im just wasting time thanks @Data_LG2

OpenStudy (anonymous):

O.o ok..even though i'm confused

OpenStudy (here_to_help15):

lol

OpenStudy (e.mccormick):

It is not 90-52. Your arc is 52 degrees, so \(\angle BOY=52^\circ\). Use that to get \(\angle BAY\)

OpenStudy (anonymous):

@here_to_help15 e.mccormick is right. Sorry if I taught you the wrong way ...

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