For 1 month, two doctors in a medical office counted the number of patients they saw each day. The mean and MAD for each doctor were calculated and recorded in a table.
What conclusion can be drawn, based upon the value of the means-to-MAD ratio?
Doctor Mean MAD
Hartmann 15.3 0.9
Kim 18.9 1.1
A.
Dr. Hartmann saw more patients per day than Dr. Kim did.
B.
Dr. Kim saw more patients per day than Dr. Hartmann did.
C.
Dr. Kim and Dr. Hartmann saw about the same number of patients per day.
D.
No conclusions can be drawn.
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OpenStudy (anonymous):
C?
OpenStudy (anonymous):
@jim_thompson5910 @pooja195
OpenStudy (anonymous):
@satellite73
OpenStudy (anonymous):
@sammixboo
OpenStudy (anonymous):
@triciaal
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jimthompson5910 (jim_thompson5910):
what numeric value did you get for the means-to-MAD ratio ?
OpenStudy (anonymous):
umm sec xD
OpenStudy (anonymous):
17?
jimthompson5910 (jim_thompson5910):
subtract the means
then divide that difference by the larger MAD value
OpenStudy (anonymous):
3.272727273
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OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (anonymous):
The MAD Is 3.272727273 @jim_thompson5910
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
if the ratio is larger than 2.5, which it is, this means that the distributions are different
so that rules out choice C. If they were similar distributions, then choice C would be the answer
OpenStudy (anonymous):
B?
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jimthompson5910 (jim_thompson5910):
which one? A or B?
OpenStudy (anonymous):
B
jimthompson5910 (jim_thompson5910):
why?
OpenStudy (anonymous):
Because The mean is Greater for Kim and so is the MAD.
OpenStudy (anonymous):
xD
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OpenStudy (anonymous):
Btw I suck at Guessing
jimthompson5910 (jim_thompson5910):
yeah the mean is larger for Kim so she takes on more patients
jimthompson5910 (jim_thompson5910):
well don't guess, all of the info you need is given
OpenStudy (anonymous):
Yeh i kinda knew but didnt know 100%
OpenStudy (anonymous):
so it is B?
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