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Convert 11.42424242 … to a rational expression in the form of a over b, where b ≠ 0.. A 11 and 42 over 999 B 11 and 42 over 9999 C 11 and 42 over 99 D 11 and 99 over 42
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@tkhunny
c it is C
That is true. Here is a way to see that: \(x = 0.4242424242...\) \(100x = 42.424242....\) subtract the first from the second and: \(99x = 42\) \(x = \frac{42}{99}\)
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