q2 – 20/500 = 0.04
q – √ 0.04 = 0.2
p – 1 – 0.2 = 0.8
p2 –0.82 = 0.64
2pq –2x(0.8)x(0.2) = 0.08
Scenario #2 Conclusion Questions

Use this information to help you answer the following questions.
The original population’s actual genotype frequencies were:

HH – 0.58; Hh – 0.26; hh – 0.16

Is the current population in Hardy-Weinberg equilibrium? Yes or No

Is the current population evolving? Yes or No

If the current population is evolving, what type of effect is responsible for genetic drift?

Question

q2 – 20/500 = 0.04
q – √ 0.04 = 0.2
p – 1 – 0.2 = 0.8
p2 –0.82 = 0.64
2pq –2x(0.8)x(0.2) = 0.08
Scenario #2 Conclusion Questions 

Use this information to help you answer the following questions.
The original population’s actual genotype frequencies were:

HH – 0.58; Hh – 0.26; hh – 0.16

Is the current population in Hardy-Weinberg equilibrium? 		Yes or No

Is the current population evolving?    					Yes or No

If the current population is evolving, what type of effect is responsible for genetic drift?