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OpenStudy (anonymous):

Of all the yoga students in a particular area, 20% study with Patrick and 80% study with Carl. We also know that 8% of the yoga students study with Patrick and are female, while 66% of the students study with Carl and are female. What is the probability that a randomly selected yoga student is female, given that the person studies yoga with Carl?

OpenStudy (anonymous):

0.35 0.56 0.69 0.83

OpenStudy (kash_thesmartguy):

D. Confirm it.

OpenStudy (ybarrap):

|dw:1433896320109:dw| The probability that a randomly chosen student is female, given that the student studies with Carl is $$ P(f|C)=\cfrac{P(f\cap C)}{P(C)} $$ Where \(f\cap C\) are the female yoga students that study with Carl and \(C\) are the yoga students who study with Carl.

OpenStudy (ybarrap):

|dw:1433896969550:dw|

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