Question

Need help!!
Solve
a) 4^x+6(4^-x)=5

Answer 1

@Nnesha

Answer 2

@mathmate @sorryimfrankie @MTALHAHASSAN2 @randomecorner @preteenpony @MTALHAHASSAN2 @BlossomCa

Answer 3

pemdas
parenthise exponets multiply divide add subtract

Answer 4

multiply both sides by 4^x

Answer 5

you will have a quadratic in terms of 4^x afterwards

Answer 6

\[4^x+6(4^{-x})=5 \\ \text{ multiply both sides by} 4^{x} \\ 4^{2x}+6(1)=5(4^x) \\ 4^{2x}-5(4^x)+6=0 \\ (4^x)^2-5(4^x)+6=0\]

Answer 7

can you finish from here?