Question

Find the exact value of the inverse trigonometric function
cos(sin^-1(root 2/3))

Answer 1

@jim_thompson5910

Answer 2

Let \[\Large \theta = \sin^{-1}\left(\frac{\sqrt{2}}{3}\right)\]
So that means \[\Large \sin(\theta) = \frac{\sqrt{2}}{3}\]

Answer 3

since \[\Large \sin(\theta) = \frac{\sqrt{2}}{3}\] this means we can draw out this triangle

Answer 4

what is the missing side?

Answer 5

wait how did you know what value corresponds with what angle/side?

Answer 6

because sine = opposite/hypotenuse