Question

which function is odd? Check all that apply.

a) y=sin(x)
b) y=csc(x)
c) y=sec(x)
d) y=cot(x)

Answer 1

i know a and b are correct. Idk about c and d

Answer 2

help

Answer 3

plz

Answer 4

do you know cos(x) is even or odd ?

Answer 5

so you can write sec(x)=1/cos(x)

Answer 6

cos(x) is even.

Answer 7

\[f(x)=\frac{1}{cosx}\\f(-x)=\frac{1}{\cos(-x)}=\frac{1}{cosx}\]
so ?

Answer 8

@Agl202

Answer 9

\[cotan(x)=\frac{sinx}{cosx}\\f(-x)=\frac{\sin(-x)}{\cos(-x)}=\frac{-sinx}{cosx}=-\frac{sinx}{cosx}=-f(x)\]

Answer 10

y = sec x = 1/cos x
substitute -x
1/ cos -x =1/cos x = sec x = y -----> even

y = sin x
substitute -x
sin -x = - sin x = -y --------> odd

y= cot x = cos x/sin x
substitute -x
cos -x / sin -x = cos x / (-sin x) = - cot x = -y ---------> odd

y = csc x = 1 / sin x
substitute -x
1/ sin -x = 1/ (-sin x)=-csc x =-y ----------> odd

Answer 11

DANG.

Answer 12

so the only function that is even is cos(x)?

Answer 13

Ya, So the other three are ur odd ones!

Answer 14

so the answer is A,B,C,D?

Answer 15

note that :sec(x) is even !!!