Question

answered

Answer 1

domain of validity is when denominators \[\neq 0\]

Answer 2

That'll help, it's also asking for the basic identity of that equation I think

Answer 3

\[\cot(\theta)=\cos(\theta)\frac{1}{\sin(\theta)}\\\frac{\cos(\theta)}{\sin(\theta)}=\cos(\theta)\frac{1}{\sin(\theta)}\\sin(\theta)\neq0\]

Answer 4

yeesh that's a lot of thetas, is that all the steps?

Answer 5

yes
and you can find where sin(theta)=0 ,then find domain (validity)