Question

Two parallel plates have an electric field strength between them of 1.0 × 10^3 N/C and an electric potential difference of 50.0 V. How far apart are the plates?

A. 1.0 cm

B. 2.0 cm

C. 5.0 cm

D. 10.0 cm

Answer 1

the requested distance is;
\[d = \frac{{\Delta V}}{E} = \frac{{50}}{{{{10}^3}}}\]

Answer 2

ok! so 0.05 m? so that means 5.0 cm? answer choice C is our solution?

Answer 3

that's right!

Answer 4

yay!! thank you!!:)

Answer 5

:)