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OpenStudy (loser66):
sin^2 = 1- cos ^2 ok?
replace and let the terms all in left hand side , the right hand side =0. Show me that step, please
OpenStudy (loser66):
Do you know how to solve quadratic ?
OpenStudy (anonymous):
no.....
OpenStudy (loser66):
But we have no way to find out the solution without quadratic. How can I help??
OpenStudy (anonymous):
a =pi
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OpenStudy (loser66):
@cutegirl I shouldn't give you a free answer because it doesn't help you on long run.
OpenStudy (anonymous):
got it
OpenStudy (loser66):
3cos a +3 = 1 - cos^2 a
cos^2a +3cosa +2=0
(cos a+2) (cos a +1) =0
cos a +2 never =0 , because it is out of range
hence , just cos a +1 =0 , then cos a =-1, hence a = pi + 2kpi.
OpenStudy (loser66):
yup. if limit is given, like from 0 to 2pi, then the answer is a =pi
if you don't have any limit, then a = pi +2kpi
OpenStudy (anonymous):
thanks so much !!!!
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OpenStudy (loser66):
I don't know, you must look at your problem (the paper) , it is not up to me.