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What is the equation of the circle with center (–4, –3) that passes through the point (6, 2)?
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Help please?
the general form for a circle of center \((h,k)\) and radius \(r\) is \[(x-h)^2+(y-k)^2=r^2\] you have \((h,k)=(-4,-3)\) so the first part should be ok
what you need is \(r^2\) which is the square of the distance between \((-4,-3)\) and \((6,2)\) use the distance formula without the square root to find it
you know how to find the distance between two points?
nevermid i got the answer wrong
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