Question

what's the vertex of x-1=1/12(y-3)^2?

Answer 1

the parabola is almost in this form

\[4a(x -h) = (y - k)^2\]

this is the general equation for a concave right parabola with a vertex (h, k)

multiply both sides of your parabola by 12 and you get

\[12(x -1) = (y - 3)^2\]

now compare your equation with the standard form above to get the vertex