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Transform each polar equation to an equation in rectangular coordinates and identify its shape. a. θ = -(π / 6) b. r = (4 / (2cosθ - 3sinθ))
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@dan815 @freckles @Luigi0210 @radar @rvc @sleepyjess
I think for A, r = 2 but I'm not sure
\[\theta=\frac{-\pi}{6}\] actually describes a line |dw:1433651567694:dw|
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