Question

Can someone help me with this problem

Solve each equation on the interval [0, 2pi].
4sin^2-3=0 is the equation

Answer 1

Actually, I think I may have got it but can someone check my answers?

Answer 2

what do you get?

Answer 3

first what do you get for sin x?

Answer 4

4sin^2x - 3 = 0
sin^2x = 3/4
sinx = √3/2 or sinx = -√3/2

Answer 5

yes correct

Answer 6

So would my answer be x= pi/3 or 2pi/3 ?

Answer 7

it asks for values in the interval 0 to 2pi and the sine can be negative or positive so there is an angle in each quadrant which satisfies the equation.

Answer 8

So I should have 4 answers then right?

Answer 9

pi/3 and 2pi/3 are 2 answers

Answer 10

yes