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evaluate the integral?
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\[\int\limits_{-1}^{1} \frac{ 3e ^{acrtan(y)} }{ 1+y^2 } dy\]
u - subbbbbb \c:/
remember your derivative of arctan(x)?
\[\Large\rm \int\limits\limits_{-1}^{1} \frac{ 3e ^{acrtan(y)} }{ 1+y^2 } dy\quad =\quad3\int\limits_{-1}^{1}e^{\color{orangered}{\arctan(y)}}\left(\color{royalblue}{\frac{1}{1+y^2}dy}\right)\]
Rememberrrrrrr? <.<
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mmmm i still didn't get it lol i tried u-sub tho. Let me post my work :)
never mind my phone is acting dumb >< but i tried to get wolfram alpha to help but it coduldnt calculate it
|dw:1433721955691:dw|So the derivative of arctan(x) is 1/(1+x^2)
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