Question

(cosΘ - cosΘ)^2 + (cos Θ + cos Θ)^2

1) sin^2Θ
2) 4
3) 8
4) cos^2Θ

Answer 1

\[\Large\rm (\color{royalblue}{\cos \theta-\cos \theta})^2+(\cos \theta+\cos \theta)^2\]\[\Large\rm (\color{royalblue}{0})^2+(\cos \theta+\cos \theta)^2\]That... should simplify things down a bit, yah? 0_o

Answer 2

With the other part as well,\[\Large\rm (\color{royalblue}{0})^2+(2\cos \theta)^2\]

Answer 3

Which isn't going to line up with any of these options...
hmmmm

Answer 4

what is the point of giving (cos(theta)-cos(theta))^2 when everyone knows its zero. Emmy will you please check the question again?

Answer 5

I truly don't know i'm taking an exam and that's exactly what the question says

Answer 6

"(cosΘ - cosΘ)^2 + (cos Θ + cos Θ)^2"<---by you


I wonder if you meant to write

\[(\cos(\theta)-\sin(\theta))^2+(\cos(\theta)+\sin(\theta))^2\]
but that would still be a choice given

Answer 7

not be a choice given*