Question

@freckles

Answer 1

Using a directrix of y = -2 and a focus of (1, 6), what quadratic function is created?

f(x) = 1/8(x - 1)2 - 2
f(x) = -1/8(x + 1)2 - 2
f(x) = -1/16(x + 1)2 - 2
f(x) = 1/16(x - 1)2 + 2

Answer 2

first little drawing:

I'm going to put the vertex midway between that horizontal line (Called y=-2) and the focus point (1,6)
We will see if you are able to tell with the vertex point is...