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What is the value of x? Round your answer to the nearest tenth if necessary.
Pythagorean theorem \[\huge\rm a^2 + b^2 = c^2 \] c is the longest side of right triangle which is hypotenuse so substitute values then solve :-)
I got 89 @Nnesha
x^2 = 89 right x = what ?
what?
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yep what ??
Pythagorean theorem \[\huge\rm (5)^2 + (8)^2 = x^2 \] 25+64 = x^2 you need x not x^2
oh, okay
okay, I got 89=x^2?
yes right now solve for x how would you cancel square of x ?
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by moving the decimal?
take square root both sides to cancel square
how do I do that
\[\huge\rm \sqrt{x} = x^\frac{ 1 }{ 2 }\] like this so take square root of x^2 and 89
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