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Mathematics 9 Online
OpenStudy (anonymous):

Please help :(

OpenStudy (anonymous):

What is the value of x? Round your answer to the nearest tenth if necessary.

Nnesha (nnesha):

Pythagorean theorem \[\huge\rm a^2 + b^2 = c^2 \] c is the longest side of right triangle which is hypotenuse so substitute values then solve :-)

OpenStudy (anonymous):

I got 89 @Nnesha

Nnesha (nnesha):

x^2 = 89 right x = what ?

OpenStudy (anonymous):

what?

Nnesha (nnesha):

yep what ??

Nnesha (nnesha):

Pythagorean theorem \[\huge\rm (5)^2 + (8)^2 = x^2 \] 25+64 = x^2 you need x not x^2

OpenStudy (anonymous):

oh, okay

OpenStudy (anonymous):

okay, I got 89=x^2?

Nnesha (nnesha):

yes right now solve for x how would you cancel square of x ?

OpenStudy (anonymous):

by moving the decimal?

Nnesha (nnesha):

take square root both sides to cancel square

OpenStudy (anonymous):

how do I do that

Nnesha (nnesha):

\[\huge\rm \sqrt{x} = x^\frac{ 1 }{ 2 }\] like this so take square root of x^2 and 89

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