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What is the length of side AB if AC is 5 sqrt 2?
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a. 5m b. 5 sqrt 2 m c. 5 sqrt 3 m d. 10m
use cosine
you should use cos which is equal =adjacent over hyp \[\huge\rm cos 45 = \frac{ x }{ 5\sqrt{2} }\] http://openstudy.com/study#/updates/5575da3ce4b0826b0eaf6c46
what is cos(45)=?
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i think its c but my math is off
|dw:1433788042810:dw|
nope c is wrong and remember it's 45 degree*
\[2 x^2=\left(5 \sqrt{2}\right)^2 \] x = 5
you can use pythagoras's theorem \[x^2+x^2=\left( 5\sqrt{2} \right)^2,x=?\]
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thank you all i think i got it :)
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