I really need help with this stuff but please explain, no direct answers
write and equation in standard form
the line has the same slope as 5x-y=7 and the same y-intercept as the graph of 2y-7x=8.
the equation in standard form is?
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OpenStudy (sdfgsdfgs):
eqn of a straight line in standard form is
y = mx + c;
where m is the slope and c is the y-intercept.
So far so good?
OpenStudy (barrelracing):
ok
OpenStudy (sdfgsdfgs):
"he line has the same slope as 5x-y=7 "
so we need to find out the slope from 5x-y=7....
can u put 5x-y=7 into the standard form of y=mx+c plz?
OpenStudy (barrelracing):
y=-5x+7
OpenStudy (barrelracing):
are you there?
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OpenStudy (sdfgsdfgs):
Ooops sorry I got distracted....almost right but it should be
y=5x-7
see where u made the mistake?
OpenStudy (barrelracing):
yes
OpenStudy (sdfgsdfgs):
So what is the slope? We need that for part of the ans :)
OpenStudy (barrelracing):
5
OpenStudy (sdfgsdfgs):
Correct! So keep that in mind and we work on finding the y-intercept ok?
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OpenStudy (sdfgsdfgs):
"(T)he same y-intercept as the graph of 2y-7x=8"
-same deal: put 2y-7x=8 into standard from y=mx+c to find the y-intercept
OpenStudy (barrelracing):
2y=7x+8
y=7/2x+4
OpenStudy (sdfgsdfgs):
GREAT job! :) so whats the y-intercept here?
OpenStudy (barrelracing):
4
OpenStudy (sdfgsdfgs):
Combining that w slope of 5, ur ans in standard form eqn is....
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