Ask your own question, for FREE!
Chemistry 14 Online
OpenStudy (anonymous):

what is the velocity of an electron traveling at 2.5 * 10^4 m/s in mph?

OpenStudy (cuanchi):

just google it ! 55923.4 mph = 5.6 *10^4 mph (two significant figures!!) 2.5 * 10^4 m/s x (1 mille/ 1.60934 * 10^3 m) x (3600s/1h)= 56250 mph

OpenStudy (anonymous):

yay figured it out:) thanks everyone:)

OpenStudy (cuanchi):

so close the question

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!