Ask your own question, for FREE!
Chemistry 17 Online
OpenStudy (anonymous):

what is the velocity of an electron traveling at 2.5 * 10^4 m/s in mph?

OpenStudy (cuanchi):

just google it ! 55923.4 mph = 5.6 *10^4 mph (two significant figures!!) 2.5 * 10^4 m/s x (1 mille/ 1.60934 * 10^3 m) x (3600s/1h)= 56250 mph

OpenStudy (anonymous):

yay figured it out:) thanks everyone:)

OpenStudy (cuanchi):

so close the question

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
VERNEISH: Two objects are moving along separate linear paths where each path is described by position, d, and time, t.
15 hours ago 1 Reply 0 Medals
Arriyanalol: i need help
2 days ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
2 days ago 8 Replies 2 Medals
Maci: what are the best stock apps for people who want to start investing?
5 days ago 3 Replies 2 Medals
Twaylor: genuienly how do i get better self control i keep watcing youtube and theres this
1 week ago 3 Replies 0 Medals
IzzyCookie: |dw:1792074056138:dw| Uhm, I don't know where to ask this, but I'm in college welding at my community college, and I need help learning vertical welding for
3 days ago 9 Replies 1 Medal
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Maci: what is your thoughts on qc reaching 10years lmk who the ogs
1 week ago 9 Replies 1 Medal
thehearken: not sure if this is considered spam, im sorry if it is, but does anyone have tips
1 week ago 2 Replies 1 Medal
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!