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Mathematics 18 Online
OpenStudy (anonymous):

In triangle FGH, FH=7feet FG=12feet and measurement F=70 degrees. Find measurement G round to the nearest tenth

OpenStudy (anonymous):

@wolf1728 @Astrophysics

OpenStudy (wolf1728):

Hello !!! I got "bumped" and I entered this topic!!!

OpenStudy (anonymous):

|dw:1433834150459:dw|

OpenStudy (anonymous):

yay and did I do that correctly?

OpenStudy (wolf1728):

I guess you did (and good diagram)

OpenStudy (anonymous):

Thats what I meant *did i do the diagram correctly*

OpenStudy (wolf1728):

Yes you did!!

OpenStudy (wolf1728):

Where's Astro?

OpenStudy (anonymous):

@Astrophysics

OpenStudy (anonymous):

not sure

OpenStudy (anonymous):

can you help me get it started and i do it and you tell me if im doing it wrong or not

OpenStudy (anonymous):

you guys there?

OpenStudy (wolf1728):

Two sides and included angle, we use Law of Cosines

OpenStudy (astrophysics):

This should not be a right triangle

OpenStudy (astrophysics):

Otherwise we could just say it's 20 degrees ;)

OpenStudy (wolf1728):

b=7 c =12 Angle A=70 degrees a^2 = (b^2 + c^2) -(2*b*c * cos(A))

OpenStudy (astrophysics):

You can use the sine law

OpenStudy (anonymous):

So one side should be longer...i was thinking the same! but 20 isnt a answer choice!

OpenStudy (astrophysics):

That would be a whole lot easier

OpenStudy (anonymous):

that is what wolf included correct

OpenStudy (astrophysics):

Not quite, he is using cosine law

OpenStudy (astrophysics):

But, I will let wolf continue :)

OpenStudy (anonymous):

does it matter which one is used or?

OpenStudy (wolf1728):

a^2 = 7^2 + 12^2 -(2*7*12*cos(70) a^2 = 49 + 144 - (108*.34202) a^2 = 193 -36.93816 a^2 = 156.06184 a = sq root(156.06184) a = 12.49

OpenStudy (anonymous):

I dont think thats correct its not a choice I have maybe we have to use Cos*b*

OpenStudy (anonymous):

hold on im looking

OpenStudy (wolf1728):

How about 11.642 ?

OpenStudy (anonymous):

how did you get that

OpenStudy (anonymous):

its one of the answers but I am trying to learn

OpenStudy (astrophysics):

Well lets redraw the triangle and put everything in place, and continue from there |dw:1433835265958:dw|

OpenStudy (astrophysics):

Oh I guess wolf already did it xD

OpenStudy (anonymous):

Ok I was just a little off on the graph

OpenStudy (wolf1728):

a^2 = 49 + 144 - (168*.34202) a^2 = 193 - (57.45936) a^2=135.54064 a = 11.6421922334 ARRGGGHHHH !!!!!!!!!!! The other time I made an arithmetic mistake.

OpenStudy (astrophysics):

I try not to make right triangles, but always end up doing so haha, and good job wolf I believe in you! :P

OpenStudy (wolf1728):

was 11.642 an answer?

OpenStudy (anonymous):

11.6 yes

OpenStudy (wolf1728):

all right !!!!!!!!!!!!!!!!

OpenStudy (astrophysics):

Alright cool! :)

OpenStudy (astrophysics):

Did you understand everything, sorry about the first question it was a bit messy, I'll go look at it again later...

OpenStudy (anonymous):

wait dont go anywhere I am gonna show you the work for a problem and I just would like for you to check

OpenStudy (anonymous):

slowly but surely I know a lot more than I did before I came here

OpenStudy (wolf1728):

all right !!

OpenStudy (anonymous):

Okay so Im finding the area of a triangle and it looks like

OpenStudy (anonymous):

|dw:1433835840125:dw|

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