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solve the following equation -sin^2 x= 2cos x-2
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is this -sin^2(x) = 2cos(x) - 2 ??
or -sin^2(x) = 2cos(x-2)?
-sin^2(x) = 2cos(x) -2
can you move all terms to left hand side to get 0 on the right?
and then use the identity sin^2(x) = 1 - cos^2(x)
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post what you get
1- cos^2(x)-2cos(x)-2=0 sorry for the late reply
@xotania_ np now can you write that as a square of 2 factors?, first combine the -2 and the +1
could you help me write that? the square of two roots
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