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Mathematics 7 Online
OpenStudy (anonymous):

solve the following equation -sin^2 x= 2cos x-2

OpenStudy (anonymous):

is this -sin^2(x) = 2cos(x) - 2 ??

OpenStudy (anonymous):

or -sin^2(x) = 2cos(x-2)?

OpenStudy (anonymous):

-sin^2(x) = 2cos(x) -2

OpenStudy (anonymous):

can you move all terms to left hand side to get 0 on the right?

OpenStudy (anonymous):

and then use the identity sin^2(x) = 1 - cos^2(x)

OpenStudy (anonymous):

post what you get

OpenStudy (anonymous):

1- cos^2(x)-2cos(x)-2=0 sorry for the late reply

OpenStudy (anonymous):

@xotania_ np now can you write that as a square of 2 factors?, first combine the -2 and the +1

OpenStudy (anonymous):

could you help me write that? the square of two roots

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