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HELP! How would I solve log3 x + log3 5 =2?
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\(log_3x+log_35=2\) hint: use rules of logarithm: \(log_b x = c\) is equivalent to \(b^c=x\) log a + log b = log ab
I don't understand how I would set up the problem?
hint: write 2 as \(\log_3 9\), and apply the other rule of logarithm.
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