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(a + b - c )(a + b + c )
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use the distributive law first multiply the second parenthesis by a then do the same with b and then -c finally simplify like terms
so whats the answer Im on a timer
sorry we are not allowed to give direct answers Only guide people to the solution.
Distribute the a to the abc on the right Then do the same for the B, distribute it to the ABC on the right Then do the same for C, distribute it to the ABC on the right
Here's the hint: \[(a+b-c)(a+b+c) =(~(a+b)~-c)(~(a+b)~+c)\]
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