Question

The area of a rectangle is 120 cm2. The length of the rectangle is eight less than the twice of the width. Find the dimensions of the rectangle.

Answer 1

so far i got....\[(2x - 8) *w=120 \right?\]

Answer 2

x=w

Answer 3

let width=x
length=2x-8
x(2x-8)=120

Answer 4

ok so i was right

Answer 5

yes

Answer 6

so... \[2x ^{2} - 8x -120=0\]

Answer 7

carry on

Answer 8

hmnmmmm

Answer 9

divide by 2

Answer 10

solve further

Answer 11

ok

Answer 12

what can i add to get 4 that i can multiply to get 60? hmm

Answer 13

10 and 6

Answer 14

x-6, and x-10?

Answer 15

1*-
60=-60
10-6=4
10*-6=-60

Answer 16

x-6, and x-10?
?

Answer 17

\[x^2-\left( 10-6 \right)x-60=0\]
\[x^2-10x+6x-60=0\]

Answer 18

thats what i got

Answer 19

\[x(x-10) 6(x-10)\]

Answer 20

good

Answer 21

6 cm and 20 cm
10 cm and 12 cm
40 cm and 30 cm
5 cm and 24 cm

Answer 22

oh multiply by 2

Answer 23

right?

Answer 24

12 and 20?

Answer 25

x(x-10)+6(x-10)=0
(x-10)(x+6)=0
x+6=0,x=-6 rejected
x-10=0,x=10
width=10
length=2*10-8=20-8=12

Answer 26

where does 8 come from?

Answer 27

oh i see

Answer 28

kinda?

Answer 29

in the statement length is 8 less than twice width