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Solve: x2 + 2x - 1 = 0
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i'm pretty sure you know how to factor that :-
That can't be factored, honestly.
i got \[-2\pm \sqrt{8}> divided by 2\]
oh wait
Looks alright to me. You can write that as \(-1 \pm \sqrt 2\)
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factor 8
square root of 8 is a long decimal
\[x^2+2x=1,add~1 ~\to~both~sides\]
\[\sqrt 8 = 2 \sqrt 2\]
\[\huge\rm \frac{ -2 \pm \sqrt{4 \times 2}}{ 2}\] yep right that's why you to factor 8 4 times 2 =8 now take square root of 4
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have**
thats what i got, but what next?
Then you've solved it.
1 + √2 and -1 - √2 -1 + √2 and -1 - √2 -1 + √3 and -1 + √2 -1 - √2 and 1 + √2
\[\huge\rm \frac{ -2 \pm 2\sqrt{ \times 2}}{ 2}\] 2 is common so take it out
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oh
so,..|dw:1433904972339:dw|
i will fan all of u if you help me with 3 questions
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