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Solve for B. A = 3(B + C) B = ((A-C) / (3)) B = ((3A-C) / (3)) B = ((A-3C) / (3))
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@Nnesha How do you make things a fraction on this website?
yep
thx
A
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the first choice? ""((A-C) / (3))""
``` \(\large\rm\frac{2}{2}\)
FIRST STEp!!! distribute parentheses by outside term
3B + 3C
yes right A = 3B +3C move 3C to the left side and then solve for b
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3C + A = 3b \[\frac{ 3C }{ 3 } + \frac{ A }{ 3 } = \frac{ 3B }{ 3 }\]
how would you cancel out 3C frm the right side ?
|dw:1433940357819:dw|
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