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Which of the following is a simplified expression equal to (comment section), for all x< -3
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\[\frac{ 9-x ^{2} }{ x-3 }\]
You can factor the numerator as a difference of squares then cancel 9 - x² = (3 - x)(3 + x)
and then (3 - x) is the same as -(x - 3)
\[\frac{ (3-x) (3+x)}{ (x-3) }=\frac{ -(x-3)(3+x) }{ (x-3) }\]
=-(3+x)=-3-x
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