write an equation in the form y=mx+b for the line which passes through (1,-10) and (-7,-2)
First we need to find the slope any ideas on how to find it?
ok know how to do that give me a min
slopes -1
ok next are you fimilar with the point slope formula?
not really can you remind me
\[\huge~y-y_1=m(x-x_1)\] m=slope int his case -1 next we select any random post lets go with (1,-10) so 1 = x1 -10=y1 now you just plug it into the formula
Are you ok with that? Do you know how to do it?
stuck? :/
a little
\[\huge~y--10=-1(x-1)\]
therefore we have \[\huge~y+10=-1(x-1)\] now distribute \[\huge~-1(x-1)\]
8
huh?
hold on messed up bad not smart at algebra at all
need help? :)
yes i need all the help i can
therefore we have \[\huge~y+10=-1(x-1)\] now distribute \[\huge~-1(x-1)\]
distribute :)
-1 * x = ? -1 * -1 =?
any thing that x right
-1x :) -1 * -1= ?
1
good so we have \[\huge~y+10=-1x+1\] we are trying to isolate y so what would the next step be?
so what your saying is get rid of 10 or change y
get rid of the 10
do i subtract 1 from 10
yes so 1-10= ?
-9
good so we get \[\huge~y=-1x-9\] thats all :)
thank you thank you thank you :)
:)
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