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Mathematics 8 Online
OpenStudy (anonymous):

last question What is the value of x? Round your answer to the nearest tenth if necessary. http://static.k12.com/calms_media/media/1577500_1578000/1577938/1/c840947ced6d410d5858579e26880ce72f28d4db/MS_IMC-150120-130106.jpg

OpenStudy (anonymous):

@Whitemonsterbunny17 @Compassionate @KyanTheDoodle

OpenStudy (godlovesme):

use the Pythagorean theorem \[a^2 + b^2 = c^2\]

OpenStudy (anonymous):

so 6^2 + 17^2=c^2

OpenStudy (godlovesme):

no 17 is the c because it's the hypotenuse so it would be \[6^2 + x^2 = 17^2\]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

and 6^2 is 36 right

OpenStudy (godlovesme):

yes :)

OpenStudy (anonymous):

and 17^2 is 289

OpenStudy (anonymous):

36+x^2=289

OpenStudy (godlovesme):

you're doing great! :)

OpenStudy (anonymous):

this is the part when i dont know what to do now

OpenStudy (anonymous):

would i subtract 36 from 289

OpenStudy (godlovesme):

ok now subtract 36 from both sides

OpenStudy (anonymous):

36-36+x^2=289-36

OpenStudy (anonymous):

x^2=253

OpenStudy (godlovesme):

good job! now take the square root of 253

OpenStudy (anonymous):

15.90

OpenStudy (godlovesme):

yep! c:

OpenStudy (anonymous):

thank you

OpenStudy (godlovesme):

anytime :)

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