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OpenStudy (babynini):
The 20th term of an arithmetic sequence is 101, and the common difference is 3. Find a formula for the nth term.
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OpenStudy (babynini):
@ganeshie8 are you free? :)
OpenStudy (babynini):
hrm, from the info given I have
a_20=a+(20-1)d
a_20=a+(19)*3
a_20=a+57
yeah?
OpenStudy (babynini):
@jim_thompson5910 :)
OpenStudy (babynini):
we know a_20
so it comes to
101=a+19(3)
a=44
so the formula for the nth term will be
a_n=44+(n-1)(3)
?
OpenStudy (jtvatsim):
You've put a lot of work into this already, so let's test your equation to verify it.
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OpenStudy (jtvatsim):
Testing a_20 seems like a good idea. Do we get the right answer?
OpenStudy (jtvatsim):
And.... we do!
OpenStudy (jtvatsim):
Looks like you've got it. Congrats!
OpenStudy (babynini):
yay! :)
OpenStudy (babynini):
thanks for checking ^-^
(how did you test a_20?)
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OpenStudy (jtvatsim):
Just plugged in n = 20.
OpenStudy (jtvatsim):
I hoped it would be 101 as the answer, and it was.
OpenStudy (babynini):
oh haha I see. Fabulous.
OpenStudy (jtvatsim):
Of course, I needed to see that n = 1 gave me 44 as claimed, but that was kind of obvious since that's what you built the formula to do. :)
OpenStudy (babynini):
Indeed :P
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