Question

Solve 6x2 + x - 1 = 0

Answer 1

do you know how you would normally solve a quadratic equation?

Answer 2

a+b=1
a x b = 6 x -1 = -6
a = 3 b=-2

6x^2 + 3x -2x - 1 = 0
3x(2x+1) -1(2x+1)
(2x+1)(3x-1)=0
x=-1/2 x=1/3

Answer 3

i got that but when u feill them in they dont work..

Answer 4

they work!

6(1/3)^2 + 1/3 - 1 = 0
6(1/9) + 1/3 - 1 = 0
2/3 + 1/3 -1 = 0
1 - 1 = 0
0 = 0

6(-1/2)^2 - 1/2 - 1 = 0
6(1/4) - 1/2 -1 = 0
3/2 - 1/2 -1 = 0
1 - 1 = 0
0 = 0