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Mathematics 22 Online
OpenStudy (anonymous):

(2/x)=(x/5x-12)

OpenStudy (anonymous):

@freckles could use your help again

OpenStudy (freckles):

multiply x and (5x-12) on both sides

OpenStudy (freckles):

\[\frac{2}{x}=\frac{x}{5x-12} \\ \frac{2}{x}(x)(5x-12)=\frac{x}{5x-12} (x)(5x-12) \\ \frac{2}{\cancel{x}}(\cancel{x})(5x-12)=\frac{x}{\cancel{5x-12}} (x)(\cancel{5x-12)} \\ 2(5x-12)=x(x) \] can you finish from here?

OpenStudy (anonymous):

@freckles actually no how do we solve for x now

OpenStudy (freckles):

this a quadratic equation have you ever solved a quadratic equation?

OpenStudy (freckles):

you can write in the form ax^2+bx+c=0

OpenStudy (anonymous):

@freckles oooohh ok thanks I see

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