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(2/x)=(x/5x-12)
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@freckles could use your help again
multiply x and (5x-12) on both sides
\[\frac{2}{x}=\frac{x}{5x-12} \\ \frac{2}{x}(x)(5x-12)=\frac{x}{5x-12} (x)(5x-12) \\ \frac{2}{\cancel{x}}(\cancel{x})(5x-12)=\frac{x}{\cancel{5x-12}} (x)(\cancel{5x-12)} \\ 2(5x-12)=x(x) \] can you finish from here?
@freckles actually no how do we solve for x now
this a quadratic equation have you ever solved a quadratic equation?
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you can write in the form ax^2+bx+c=0
@freckles oooohh ok thanks I see
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