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Calculate the values of x if @ganeshie8
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\[3^{2x+1}-3^{x+2}=3^{x+3}-3^4\]
let \(t=3^x\) and make a quadratic in terms of \(t\)
\[t(3^3)-t(3^2)-t(3^3)=-3^4\]
\[t(3^3-3^2-3^3)=-3^4\]\[t(9)=81\]
\[t=9\]
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\[x=2\]
Like this? @mukushla
except that\[3^{2x+1}=3t^2\]
\[3t^2-9t-27t+81=0\]
\[3t^2-36t+81=0\]
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\[3(t^2-12t+27)=0\]
\[t=3,t=9\]
\[3^x=3^1,3^x=3^2\]
\[x=1,x=2\]
Thnx @mukushla
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