Question

Mike and his friends bought cheese wafers for $2 per packet and chocolate wafers for $1 per packet at a carnival. They spent a total of $25 to buy a total of 20 packets of wafers of the two varieties.

Part A: Write a system of equations that can be solved to find the number of packets of cheese wafers and the number of packets of chocolate wafers that Mike and his friends bought at the carnival. Define the variables used in the equations.

Part B: How many packets of chocolate wafers and cheese wafers did they buy?Explain how you got the answer and why you selected a particular me

Answer 1

Alright so system of eqations:
Lets call the amount of chocolate wafer packets (c) and the amount of cheese wafer packets (h)
They bought a total of 20 packets so:
c + h = 20
They spent $25 dollars, and chocolate packets were $1 while cheese were $2, so:
c(1) + h(2) = 25

Answer 2

Do you get it so far?

Answer 3

yes!

Answer 4

Alright awesome :)
next part, to solve for this, we just use substitution

Answer 5

alright

Answer 6

I think you should try this one out yourself before I give you any answers :P
Hint: Solve for h first by making the first equation into c = bla bla bla

Answer 7

5

Answer 8

Do you want to show me your steps and how you got there or are you in a bit of a rush to get something done?

Answer 9

or 15?...-_-

Answer 10

no rush

Answer 11

Alright, so show me step by step what you did and I will guide you in the right direction to the best of my abilities

Answer 12

Remember, you're plugging the first equation into the second equation once you make the first one c = 20 - h

Answer 13

and because you have the variable c in the second equation, you just plug 20- h in as c, and therefore you only have to solve for one variable instead of two making things much easier

Answer 14

x+y=20
2x+5=25
then x=5
y=15

Answer 15

So first thing, always use the given variables, don't change them or you have a lot bigger chance of becoming confused

Answer 16

try again with that in mind

Answer 17

ok

Answer 18

now im confused:(

Answer 19

do i subtract 1 from 2 ?

Answer 20

I'm sorry, I got distracted.
Alright I will show you how to do it step-by-step

Answer 21

im now in a rush

Answer 22

:'(

Answer 23

c + h = 20
c + 2h = 25
That is our system of equations, now we solve for one variable, then use that value to solve for the other variable:
c + h = 20 --> c = 20 - h
Using this, we plug it into the second equation:
(20 - h) + 2h = 25 --> h = 5
h = 5 back into the first equation, c + 5 = 20, c = 15

Answer 24

If you need me to rewrite everything for you to answer the questions more easily tell me

Answer 25

thanks so much!!!

Answer 26

No problem :) If you have more questions to answer just paste them in here quickly, and I will answer them

Answer 27

your awesome!!

Answer 28

Well thank you :D

Answer 29

So whenever you're ready

Answer 30

how old are you?

Answer 31

i dont have anymore, all done(:

Answer 32

I am 16, and you?

Answer 33

15

Answer 34

same! what part

Answer 35

i am but im doing a "refresher course"

Answer 36

I have to do my own final 4 tests for the second segment of Algebra II Honors however, anytime at all, just ask me and I will respond as fast as I can :)