Question

Trig/ Pre Cal. How do I do this? I need to work out these using Trig identities

\( tan^2 + 5 = sec^2 + 4 \)
\( \frac{sin^2}{cos^2} + 5 = sec^2 + 4 \)
Am I on the right path? What should I do next?

Answer 1

well....i think we can write 5 as 1+4

Answer 2

\[\huge\rm tan^2 +5 = \tan^2 +1+4\]
like this
then use this identity 1+tan^2 = sec^2

Answer 3

i guess.....

Answer 4

\( \frac{1-cos^2}{1-sin^2} + 5 = sec^2 + 4 \)
Is this the right path? How do I get the left side to = \( sec^2 + 4 \)

Answer 5

if you do the other way like i did
tan^2 +1+4
now you can apply this identity (1+tan^2) =sec^2
= done!
2 steps

Answer 6

tan^2+1+4 = tan^2+5 but I need tan^2 + 5 to equal sec^2+4 How does tan^2 become sec^2? Only 1+tan^2 = sec^2

Answer 7

yes that's right that's why i wrote 1+4 instead 5
now you can apply that identity\[\huge\rm \color{reD}{tan^2 +1}+4 = sec^2 +4 \]

Answer 8

tan^2 + 1 is same as 1+tan^2 \[\huge\rm \color{reD}{1+tan^2 }+4 = sec^2 +4 \]

Answer 9

I have tan^2 on the left said. You are saying tan^2 = 1+tan^2. You just through out tan^2 and put in 1+ tan^2 but tan^2 does not = 1+tan^2

Answer 10

nope i never said that tan^2 = 1+tan^2
well start it again
\[\huge\rm tan^2 +5\] is same as \[\tan^2 +1+4\]
agree or no ??

Answer 11

1+4 =5
you can write 5 as 1+4

Answer 12

AH I see!!! Man that was right in front of me.. I was way over thinking this thing lol

Answer 13

yaya!!! :-)

Answer 14

i can understand
i guess helping other users and PRACTICE help me to find out easy way :-)

Answer 15

just practice practice and practice :-)

Answer 16

Thank you for showing me the light :-)

Answer 17

haha my pleasure!!! :-)