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OpenStudy (anonymous):
2tan37.tan53 - sec65/cosec25 + tan^2(45)
@Pawanyadav
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OpenStudy (anonymous):
Show the steps.
OpenStudy (anonymous):
???
I'm confused :(
OpenStudy (pawanyadav):
{2tan37tan65=2}
{tan^2(45)=1}
{sec65/cosec25=sin25/cos65=sin(90-65)/cos65
=cos65/cos65=1}
Now put all three values in question.
OpenStudy (anonymous):
It's
2tan37.tan53 and not 2tan37.tan65
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OpenStudy (pawanyadav):
Yes, my mistake.sorry
Do you understand now
OpenStudy (anonymous):
No :(
OpenStudy (pawanyadav):
Which part you not understand.
OpenStudy (anonymous):
The whole thing.
OpenStudy (anonymous):
2tan37.tan53=2
sec65/cosec25=1
tan^2(45)=(TAN45)^2=1
S0,
2-1+1 =2
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OpenStudy (anonymous):
How is
2tan37.tan53 = 2?
OpenStudy (anonymous):
YOU ASKED THAT QUESTION IN UR RECENT POST
OpenStudy (anonymous):
Yeah.Okay,but then my net went off for DAYS so............
OpenStudy (pawanyadav):
2×3/4×4/3=2
In this 3/4 And4/3 are values of tan37 and tan53
OpenStudy (anonymous):
And Thanks Yaar @Pawanyadav
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OpenStudy (anonymous):
SO HOPE U NOW UNDERSTAND ?
OpenStudy (anonymous):
Why are you yelling?
OpenStudy (anonymous):
HMMMM.SORRY .
IT WAS JUST A QUESTION TO SEE IF YOU UNDERSTAND NOW
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