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Mathematics 18 Online
OpenStudy (anonymous):

what is the name and official definition of the rule that allows this? n/(anything)^x = n (anything)^-x

OpenStudy (loser66):

reciprocal??

OpenStudy (alekos):

\[\frac{ 1 }{a ^{ x} } = a ^{-x}\] I reckon that would be the definition of a negative exponent

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