Question

Needing assistance with "Factor the polynomial using the grouping number method"

Answer 1

4a^2 -7a+3

(4)(3)=12

Product-- --> Sum
(-1)(-12)=12--> -13
(-2)(-6)=12 -->-8
(-3)(-4)=12 -->-7 <--

4a^2 -7a+3= 4a^2 -3a-4a+3
(4a^2 -3a) - (-4a+3) ---Stuck here

Answer 2

lets switch it
\[\huge~\rm ~(4a^2 --4a) - (3a+3)\]

Answer 3

lets switch it
\[\huge~\rm ~(4a^2 +4a) - (3a+3)\]

Answer 4

now you can solve it :)

Answer 5

Why'd you switch it though????? O.o

Answer 6

To make it easier to solve

Answer 7

it doesnt matter what order you put the a's in

Answer 8

Answer-- (a+1)(4a-3)

Answer 9

You just switch them around? Theres no minus or plus to cross then to the other side?

Answer 10

yes thats right :)

Answer 11

Alright I have another one

Answer 12

ok repost it :)

Answer 13

4x^2 +7x+3
(4)(3)=12

Same product as before
(-3)(-4)=12-->-7

4x^2 +7x+3= 4x^2 -3x-4x+3
(4x^2 -3x) - (-4x+3)

Answer 14

same thing
\[\huge~\rm~(4x^2 -3x) - (-4x+3)\]
\[\huge~\rm~(4x^2 +4x) - (-3x+3)\]

Answer 15

Answer-- (x+1)(4x-3)

Answer 16

somethings wrong..... :L
(x+1)(4x-3)
(x+1)(4x+3) <--answer

Answer 17

Okay!

Answer 18

hope i helped :)

Answer 19

I got the first one wrong.. Correct answer-- (4a-3)(a-1)

Answer 20

It was your math...
However switching it does not make a diffrence.

Answer 21

But that should have been right.... :/

Answer 22

You told me + and a -
the correct answer had two -

Your switching told me to change the signs. My math was correct till then

Answer 23

oh right the signs i think i made a mistake in switching the signs! sorry! :( Did you get the 2nd one right?

Answer 24

Yes the second one was correct.. Its fine I still got a 90%

Answer 25

hmmm sorry about that its still an A :/ sorry :(

Answer 26

Its okay just wish I had check it.. Thank you for your help

Answer 27

:)