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5(x + 2) greater than or equal to 7x + 2(x − 1) I need help
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so I guess you need to solve for x, is that right?
yes can you please help me?
\[5(x+2) \ge 7x+2(x-1)\]
so lets start with the LHS and expand
ok so we distribute first right
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yep
over to you
so it will be 5x and 2x
5(x + 2) greater than or equal to 7x + 2(x − 1) 5x + 10
7x + 2x-2
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5x +10 < 9x-2
NO \[5x+10\ge9x-2\]
Now you'll need to get x's on the left and constants on the right
@smart103 What was the correct answer?
Next step is \[5x-9x \ge -2-10\]
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then we have \[-4x \ge-12\]
multiply both sides by -1 \[4x \le12\]
finally divide both sides by 4 \[x \le3\]
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