Question

How does this model demonstrate the Pythagorean Theorem?

http://static.k12.com/calms_media/media/1578000_1578500/1578333/1/83631eddd15e258c3a715d653ee6b23d0d38eb4b/MS_IMC-150120-1130201.bmp

Answer 1

you should post this in math not history

Answer 2

A. The sum of the lengths of the shortest and the longest sides is equal to twice the length of the middle side. So double the length of the longer leg of any right triangle is equal to the sum of the shorter leg and the hypotenuse.

B. The sum of the area of the two smaller squares is equal to the area of the larger square. So the sum of the lengths of the two legs of any right triangle squared is equal to the length of the hypotenuse squared.

C. The sum of the area of the smallest and the largest squares is equal to the area of the middle square. So the sum of the lengths of the shorter leg and the hypotenuse of any right triangle squared is equal to the length of the middle leg squared.

D. The length of the longest side minus two equals the length of the middle side. The length of the middle side minus two equals the length of the shortest side. So the length of the short leg of any right triangle is equal to the length of the middle leg minus 2, and the length of the hypotenuse is equal to the length of the middle leg plus 2.

Answer 3

OOPS! i thought this was math ill delete this XD sorry

Answer 4

np man

Answer 5

B is your best choice but it is very badly stated. This gives an EXAMPLE of the Pythagorean theorem. It does NOT demonstrate it. Furthermore, B is written incorrectly, it should say "sum of squares of the lengths of the legs", NOT "sum of the lengths of the two legs of any right triangle squared".

Answer 6

right true

Answer 7

oh ok thankyou! I was kind of confused by this question XP

Answer 8

yup