Question

How do you graph y=x^2-4x+3 I need the vertex, axis of symmetry, y and x axis as well

Answer 1

one way to do this is "complete the square"
so that you can write the equation in the form
y=a(x-h)^2 +k

see http://www.mathwarehouse.com/geometry/parabola/standard-and-vertex-form.php

Answer 2

How do you find the vertex I'm still a little confused

Answer 3

first complete the square
x^2-4x+3
x^2-4x=-3
-4/2=-2
-2^2=4 so add four to both sides of the equation
x^2-4x+4=1
now factor the left side of the equation to get
(x-2)^2=1
subtract 1 from both sides
(x-2)^2-1=0
This is now in the form (x-h)^2+k
the vertex is (h,k)
so for your equation the vertex is (2,-1)
the axis of symmetry is x=k
so x=-1