Question

How do you graph y=x^2-4x+3 I need the vertex, axis of symmetry, y and x axis as well will give medal

Answer 1

complete the square on R.H.S.

Answer 2

\[y=x^2-4x+4-4+3=(x-2)^2-1\]
\[(x-2)^2=y+1\]
it is an upward parabola with vertex (2,-1)

Answer 3

axis of symetry is x-2=0 or x=2

Answer 4

it cuts y-axis at (0,3)

Answer 5

it cuts x-axis where y=0
\[(x-2)^2=1,x-2=\pm1,x=?\]

Answer 6

Thank you

Answer 7

yw