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Mathematics 23 Online
OpenStudy (anonymous):

Help me with factoring for a medal?

OpenStudy (anonymous):

9x^2 + 3x - 2 = 0 How would I factor this?

pooja195 (pooja195):

-2*9=-18 |dw:1434501674955:dw| (9x^2-3x)+(6x-2) Factor left side of equation. (3x−1)(3x+2)=0 Set factors equal to 0. 3x−1=0 or 3x+2=0

OpenStudy (lulubj):

mm yeah, thats the answer

pooja195 (pooja195):

no its not

OpenStudy (lulubj):

how is it not

OpenStudy (lulubj):

(3x-1)(3x+2)?

pooja195 (pooja195):

3x−1=0 or 3x+2=0 SOLVE <---this is why its not 3x-1=0 3x+2=0

pooja195 (pooja195):

u need to solve for x in the TWO SEPARATE equations so you end up with 2 answers

OpenStudy (anonymous):

So I'm a bit confused with your first post. 9*-2=-18, but why did you put (9x^2-3x)+(6x-2)?

pooja195 (pooja195):

because that is factoring by grouping

OpenStudy (anonymous):

Oh okay. But I'm still confused on how exactly you factor. So can we take this step by step?

OpenStudy (anonymous):

Okay, this is helpful yes. But I've been up all day, since 2 in the morning doing nothing but tests and essays. And I can hardly think. Right now, all that text is overwhelming me to the point where I can't even think when I look at all that.

pooja195 (pooja195):

this is a test?

OpenStudy (anonymous):

If I'm not how I am now, then I would be able to read all that no problem. But I'm at the point where too much text overwhelms me

OpenStudy (anonymous):

No, this is an assignment. I'm assigned to factor this specific question twice, each with a different factoring method

pooja195 (pooja195):

http://www.mathsisfun.com/algebra/factoring.html this should be easier:)

OpenStudy (anonymous):

OH MY GOD SO MUCH BETTER. YOUR A GODDESS! Haha, thanks!

pooja195 (pooja195):

:)

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