Question

A rock is launched from a cannon. Its height, h(x), can be represented by a quadratic function in terms of time, x, in seconds.
After 1 second, the rock is 58 feet in the air; after 2 seconds, it is 112 feet in the air.
Find the height, in feet, of the rock after 10 seconds in the air.

Answer 1

@crissyyyxoxo

Answer 2

h(x) = ax - bx^2

h(1) = a - b = 58 => a = b + 58

h(2) = 2a - 4b = 112

2(b + 58) - 4b = 112

- 2b + 116 = 112

2b = 4 => b = 2

so a = 2 + 58 = 60

so h(x) = 60x - 2x^2

so h(10) = 600 - 200 = 400 ft